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A model rocket rises with constant acceleration to a height of 3.7m , at which p

ID: 1274618 • Letter: A

Question

A model rocket rises with constant acceleration to a height of 3.7m , at which point its speed is 26.0m/s .

Part A

How much time does it take for the rocket to reach this height?

Express your answer using two significant figures.

Part B

What was the magnitude of the rocket's acceleration?

Express your answer using two significant figures.

Part C

Find the height of the rocket 0.10s after launch.

Express your answer using two significant figures.

Part D

Find the speed of the rocket 0.10s after launch.

Express your answer using two significant figures.

Explanation / Answer

u = 0

by 3rd eq . v^2-u^2=2as

         = 26^2-0=2a*3.7

       so a = 91 m/s^2

PART A

v=u+at

26=0+ 91t

so t = 0.28 sec

PART B

a= 91 m/s^2

PART C

s= ut+1/2 at^2

s= 0 + 1/2 (91*0.10^2)

s= o.45 m

PART D

v=u+at

v= 0+ 91*0.10 = 9.1 m/s

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