A jet airplane touches down on an airport runway with a speed of 187 km/hr. It s

Question

A jet airplane touches down on an airport runway with a speed of 187 km/hr. It slows at a constant rate to a stop over a time period of 8.71 s. How far does the jet travel along the runway before stopping?

A boy stands on a bridge 17.1 m above the water, and he drops a water balloon on a boat of unsuspecting tourists. The boat is traveling at a constant speed of 11.3 m/s (toward the bridge), and the boy manages to hit a tourist on the boat with the balloon. How far away from the base of the bridge was the boat when the boy released the balloon?

Explanation / Answer

187000 m/hr = 51.944 m/s and to lose that much speed in 8.71 s you must decelerate at 51.944/8.71 = 5.9638 m/s2. The distance you travel is vt + at2/2 = (51.944 m/s)(8.71 m/s) + (-5.9638 m/s2)(8.71 s)2/2 = 226.2 m

In Earth's gravity the time to fall 17.1 meters can be found by solving d = at2/2 for t: t = (2d/a)1/2 = ((2 * 17.1 m)/(9.81 m/s2))1/2 = 1.8671 s. In that time, the boat had to have traveled 1.8671 * 11.3 = 21.1 m.

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