A jet at 121 m/s, banks to make a horizontal circular turn. The radius of the tu

Question

A jet at 121 m/s, banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2.00x10^5 kg. Calculat magnitude of the necessary lifting force.

I have tried this problem multiples times myself but never seem to comeout with the right answer. When I do it I find the horizontal and vertical components seperatly then add them together. So I will us the equations:
y= mass of the plane * gravity
x= (mass of the plane * v^2)/ R
total= square root of x^2+y^2
Therefore the answer would be 1.65x10^6 , but it doesn't seem to be correct. Can anyone help?? Please and thank you!

Explanation / Answer

The lift will both cause the circular motion and keep the altitude of the plane. The vertical component will be the weight of the place. The radial (horizontal) force will be the circular motion.

F=mv2/r

F=2x105(121)2/3810

F=768556 N

so the lift is

L=(7685562+(2x105*9.8)2)

L=2105297 N= 2.1 MN

hope that helps

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