A table is 1.43 m above the surface of a flat floor. Odie (a dog) is running aft

Question

A table is 1.43 m above the surface of a flat floor. Odie (a dog) is running after Garfield (a cat) across the surface of the table. Garfield steps out of the way at the last second, and Odie slides off the edge of the table at a speed of 4.7 m/s. a. Sketch a y vs. x graph for Odie while he is in freefall. b. Where will Odie strike the floor? (find the horizontal distance from the edge of the table) c. What will be the velocity components of Odie just before he hits the floor? d. What will be the velocity (magnitude and direction) of Odie just before he hits the floor?

Explanation / Answer

first find time in the y direction
(assuming down is positive)
Yfinal = Yinitial + (Vinitial * Time) + (Acceleration/2*Time^2)
4.7 = 0 + (0 * T) + (9.81/2 * T^2)
4.7 = 4.905T^2
T^2 = .9582
time = .9788

Now plug time into the x position coordinate

Xfinal = 0 + (4.7 * .9788) + (0/2 t^2)
Xfinal = 4.7 * .9788
Xfinal = 4.60073
thats the asnwer for b

for C use this equation
Vfinal = Vinitial + Acceleration*time

we know the 3 so we can calculate the y velocity
V = 0 + -9.81(.9788)
Vyfinal = -9.6028

Vfinal on the X direction remains constant so Vxfinal = 4.7

for part d you must use Pythagorean theorem
a^2 + b^2 = c^2
so square both velocities and get the square root

4.7^2 + -9.6^2 = c^2
c= 10.69 m/s

now to get the direction you must use sin cos and tan to get the angle of direction

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