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A physics book slides off a horizontal table top with a speed of 1.05m/s . It st

ID: 1277208 • Letter: A

Question

A physics book slides off a horizontal table top with a speed of 1.05m/s . It strikes the floor after a time of 0.360s . Ignore air resistance

part a Find the height of the table top above the floor.

part b Find the horizontal distance from the edge of the table to the point where the book strikes the floor.

part c Find the horizontal component of the book's velocity just before the book reaches the floor.

part d Find the vertical component of the book's velocity just before the book reaches the floor.

part e Find the magnitude of the book's velocity just before the book reaches the floor.

part f Find the direction of the book's velocity just before the book reaches the floor.

Explanation / Answer

For the first part, assuming there is no initial vertical velocity (which in this case, there is not), T = sq. rt. (2h/g) where T is time, h is the vertical height that it falls, and g is the acceleration due to gravity. 0.350 = sq. rt. (2h/9.8) .1223 = 2h/9.8 2h = 1.2005 h = about .6 meters d = v t where d = distance, v = velocity, and t = time. d= (1.10)(0.350) = 0.385 meters

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