A 200 g plastic ball is at rest on a frictionless incline 0.658 m above the surf

Question

A 200 g plastic ball is at rest on a frictionless incline 0.658 m above the surface of a table. The ball then rolls down the incline and across the table coming to rest after a distance of 2.45 m . What is the average friction on the ball while rolling across the table? A 200 g plastic ball is at rest on a frictionless incline 0.658 m above the surface of a table. The ball then rolls down the incline and across the table coming to rest after a distance of 2.45 m . What is the average friction on the ball while rolling across the table?

Explanation / Answer

First by conservation of energy

mgh = .5mv2

(9.8)(.658) = .5(v)2

v = 3.59 m/s

Then apply vf2 = vo2 + 2ad

0 = 3.592 + 2a(2.45)

a = 2.632

Finally F = ma

F = .2(2.632)

F = .564 N

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