Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A 20.0 mL sample of NaCl solution has a mass of 21.040 g. After the solution is

ID: 891369 • Letter: A

Question

A 20.0 mL sample of NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution. A) Mass/Mass% B)Mass/Volume% C)Molarity(M) A 20.0 mL sample of NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution. A) Mass/Mass% B)Mass/Volume% C)Molarity(M) A) Mass/Mass% B)Mass/Volume% C)Molarity(M)

Explanation / Answer

A 20.0 mL sample of NaCl solution has a mass of 21.040 g. After the solution is evaporated to dryness, the dry salt residue has a mass of 4.348 g. Calculate the following concentrations for the NaCl solution.

A) Mass/Mass% = (dry salt mass / original mass ) x 100

                             = (4.348/ 21.040 ) x 100

                            = 20.66

B)Mass/Volume% = (4.348 / 20 ) x 100

                               = 21.74%

C)Molarity(M) = moles of solute in 1 litre solution

moles = mass / molar mass

NaCl molar mass = 58.5

moles = 4.348 / 58.5 = 0.07432

molarity = (0.07432 / volume ) x 1000

              = (0.07432 /20) x1000

              = 3.71 M

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote