A blue point charge q 1 = 3.95nC is placed at x = 0.196m , and a purple point ch

Question

A blue point charge q1 = 3.95nC is placed at x= 0.196m , and a purple point charge q2 = 5.01nC is at x= -0.296m .

1. What is the magnitude of the total force exerted by these two on a point charge q3 = -5.95nC that is placed at the origin? (Watch your signs).

2. What is the direction of the total force exerted by these two charges on a negative point charge q3 = -5.95nC that is placed at the origin? Multiple Choice.

A. To the +x direction.

B. To the -x direction.

C. Perpendicular to the x-axis.

D. The force is 0.

Explanation / Answer

Fnet = F1 + F2

F = kq1q2/r^2

Fnet = 9*10^9*5.95*3.95*10^-18 / 0.196^2 -   9*10^9*5.95*5.01*10^-18 / 0.296^2

Fnet = 2.444 * 10^-6 N

A. To the +x direction.

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