Suppose the period of a pendulum is measured to be 1.71 +/- 0.04s. What is T^2 i

Question

Suppose the period of a pendulum is measured to be 1.71 +/- 0.04s.

What is T^2 in numerical value and units?

To find the rror in T^2 we first need to find the relative error in T. The relative rror in T is given by the forumla DeltaT/T. Now we can find the relative error in T^2 by multuplying the relative rror in T by 2. We finally need to convert the relative error in T^2 in to the absolute error.

Thank you!

What is the forumla for the absolute error in T^2? And its numerical value and units are?

Explanation / Answer

relative error in T^2 = 2*T*DeltaT/ (T ^2) = Delta(T^2)/ (T ^2)

so the absolute error in T^2 = mod ( 2*T*DeltaT )

= mod(2*1.71*0.04)

= 0.1368

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