NO LONGER NEED HELP. Figured it out. Thanks anyway. Tom now pushes eight identic

Question

NO LONGER NEED HELP. Figured it out. Thanks anyway.

Tom now pushes eight identical blocks on the horizontal and frictionless table (he's compulsive). The force that block 1 exerts on block 2 is F12; the force that block 7 exerts on block 8 is F78. What is the ratio F12/F78?

(A) 1

(B) 1/8

(C) 7

(D) 1/7

(E) 8

NO LONGER NEED HELP. Figured it out. Thanks anyway. Tom now pushes eight identical blocks on the horizontal and frictionless table (he's compulsive). The force that block 1 exerts on block 2 is F12; the force that block 7 exerts on block 8 is F78. What is the ratio F12/F78? (A) 1 (B) 1/8 (C) 7 (D) 1/7 (E) 8

Explanation / Answer

Total net force on block 2 is,

                Fpush = (m+m)a

              = 2(ma)

               = 2F12

Total net force on block 8 is [From 1 to 8 blocks we have 7 pairs of forces],

                Fpush = 7[2ma]

                         = 14 ma

                         = 14 F78

Compare the two equations, we get

                  2F12 = 14 F78

Thus, the value of the ratio F78 / F12 is,

              F12 / F78 = 14/2

                             = 7

Therefore, option (C) is correct.

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