A simple Atwood\'s machine uses two masses, m 1 and m 2 . Starting from rest, th

Question

A simple Atwood's machine uses two masses, m1 and m2. Starting from rest, the speed of the two masses is 7 m/s at the end of 7 s. At that instant, the kinetic energy of the system is 87 J and each mass has moved a distance of 24.5 m. Determine the values of m1 and m2.
m1 =

kg

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2)

m2 = kg

A simple Atwood's machine uses two masses, m1 and m2. Starting from rest, the speed of the two masses is 7 m/s at the end of 7 s. At that instant, the kinetic energy of the system is 87 J and each mass has moved a distance of 24.5 m. Determine the values of m1 and m2. m1 = kg You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. Your submissions: 2) m2 = kg

Explanation / Answer

v=at

7=7t

a=1m/s^2

a=(m1-m2)g/(m1+m2)

m1+m2=g(m1-m2)...........1

k.e=1/2(m1+m2)v^2

87=1/2(m1+m2)7^2

m1+m2=3.55kg..................2

put 2 in1

m1-m2=3.55/9.81=0.36.......3

add 2 and 3

m1=1.96kg

m2=1.59kg

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