An electron at point A in the figure ( Figure 1 ) has a speed v 0 of 1.4010 6 m/
ID: 1283536 • Letter: A
Question
An electron at point A in the figure (Figure 1) has a speed v0 of 1.40106m/s .
Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Find the time required for the electron to move from A to B.
An electron at point A in the figure (Figure 1) has a speed v0 of 1.40 10^6 m/s . Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B. Find the time required for the electron to move from A to B.Explanation / Answer
m*v^2/r = q*v*B
==> B = m*v/(r*q)
= 9.1*10^-31*1.4*10^6/(0.05*1.6*10^-19)
= 1.59*10^-4 T or 0.159 mT
t = T/2
= (2*pi*r/v)/2
= pi*r/v
= pi*0.05/1.4*10^6
= 1.12*10^-7 s
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