Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

An electron at point A in the figure ( Figure 1 ) has a speed v 0 of 1.4010 6 m/

ID: 1283536 • Letter: A

Question

An electron at point A in the figure (Figure 1) has a speed v0 of 1.40106m/s .

Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.

Find the time required for the electron to move from A to B.

An electron at point A in the figure (Figure 1) has a speed v0 of 1.40 10^6 m/s . Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B. Find the time required for the electron to move from A to B.

Explanation / Answer

m*v^2/r = q*v*B

==> B = m*v/(r*q)

= 9.1*10^-31*1.4*10^6/(0.05*1.6*10^-19)

= 1.59*10^-4 T or 0.159 mT


t = T/2

= (2*pi*r/v)/2

= pi*r/v

= pi*0.05/1.4*10^6

= 1.12*10^-7 s

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote