A film of oil, with an index of refraction of 1.48 and a thickness of 2.00 cm, f

Question

A film of oil, with an index of refraction of 1.48 and a thickness of 2.00 cm, floats on a pool of water, as shown in the figure. A beam of light is incident on the oil at an angle, ?i = 54.0 to the vertical.

(a) Find the angle ? the light beam makes with the vertical as it travels through the water.

A film of oil, with an index of refraction of 1.48 and a thickness of 2.00 cm, floats on a pool of water, as shown in the figure. A beam of light is incident on the oil at an angle, ?i = 54.0½ to the vertical. (a) Find the angle ? the light beam makes with the vertical as it travels through the water. ½

Explanation / Answer

sin i/sin r = 1.48 [For air oil medium]

so Sin r = sin 54/1.48 = 0.5466

For oil water medium the incidence angle = r from air oil medium

let r2 be refractive angle in water

so sin r/ sin r2 = 1.33/1.48

sin r2 = 0.5466 * 1.112 = 0.607

r2 = 37.43 degress with normal

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