A block of mass m = 2.02 kg slides down an ? = 31.8 incline which is h = 3.56 m

Question

A block of mass m = 2.02 kg slides down an ? = 31.8 incline which is h = 3.56 m high. At the bottom, it strikes a block of mass M = 7.22 kg which is at rest on a horizontal surface, as seen in figure below. (Assume a smooth transition at the bottom of the incline.) If the collision is elastic, and friction can be ignored, determine the speed of the smaller block after the collision.

-4.701 m/s

Determine the speed of the bigger block after the collision.
3.652 m/s

Determine how far back up the incline the smaller mass will go???

You are correct.
Your receipt no. is 158-2830 Previous Tries A block of mass m = 2.02 kg slides down an ? = 31.8 incline which is h = 3.56 m high. At the bottom, it strikes a block of mass M = 7.22 kg which is at rest on a horizontal surface, as seen in figure below. (Assume a smooth transition at the bottom of the incline.) If the collision is elastic, and friction can be ignored, determine the speed of the smaller block after the collision. -4.701 m/s Determine the speed of the bigger block after the collision. 3.652 m/s Determine how far back up the incline the smaller mass will go???

Explanation / Answer

mgh = mv2/2

h=v2/2g= 4.7012/2g=1.275m

let distance travelled up the incline be d

d sin 31.8 = 1.275

d=1.275/.527=2.419m ans

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