Determine the maximum angle ? for which the light rays incident on the end of th
ID: 1284544 • Letter: D
Question
Determine the maximum angle ? for which the light rays incident on the end of the light pipe in the figure below are subject to total internal reflection along the walls of the pipe. Assume the light pipe has an index of refraction of 1.39 and the outside medium is air.
Explanation / Answer
C = sin^-1(1/u) = 46
1*sintheta = 1.39*sin(90-46)
theta = 74.5 degrees
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