A traffic light hangs from a pole as shown in ( Figure 1 ) .The uniform aluminum
ID: 1284647 • Letter: A
Question
A traffic light hangs from a pole as shown in (Figure 1) .The uniform aluminum pole AB is 7.90m long and has a mass of 13.5kg . The mass of the traffic light is 23.0kg .
A.) Determine the tension in the horizontal massless cable CD. Express your answer to two significant figures and include the appropriate units.
B.) Determine the vertical component of the force exerted by the pivot A on the aluminum pole. Express your answer to two significant figures and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward.
C.) Determine the horizontal component of the force exerted by the pivot A on the aluminum pole.Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the force is to the right and negative value if the direction of the force is to the left.
A traffic light hangs from a pole as shown in (Figure 1) .The uniform aluminum pole AB is 7.90m long and has a mass of 13.5kg . The mass of the traffic light is 23.0kg . A.) Determine the tension in the horizontal massless cable CD. Express your answer to two significant figures and include the appropriate units. B.) Determine the vertical component of the force exerted by the pivot A on the aluminum pole. Express your answer to two significant figures and include the appropriate units. Enter positive value if the force is upward and negative value if the force is downward. C.) Determine the horizontal component of the force exerted by the pivot A on the aluminum pole.Express your answer to two significant figures and include the appropriate units. Enter positive value if the direction of the force is to the right and negative value if the direction of the force is to the left.Explanation / Answer
a) balancing moment about pivot point ,
Tsin37 x (3.80 /sin 37) - 13.5gcos37 x (7.90 /2) - 23g cos37 x 7.90 = 0
T = 484.07 N
b) balancing forces in vertical direction :
Fy = 13.5g + 23g = 357.7 N
c) in horizonrtal direction,
Fx =T = 484.07 N
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