Two capacitors are connected to an AC source as shown in the figure. Assume VAC

Question

Two capacitors are connected to an AC source as shown in the figure. Assume VAC = Vmax sin(2pi f t), with Vmax = 13 V and f = 2028 Hz.

- The image just shows what it looks like.

What is the (peak value) of the current through the capacitors?

=____A

What is the rms current?

=____A

Two capacitors are connected to an AC source as shown in the figure. Assume VAC = Vmax sin(2pi f t), with Vmax = 13 V and f = 2028 Hz. - The image just shows what it looks like. What is the (peak value) of the current through the capacitors? What is the rms current?

Explanation / Answer

Ceq= (2*1)/(2+1) = 2/3

Current through Ceq is given by i = 1/Ceq * dVac/dt

i= 3/2 * Vmax * Cos ( 2Pi*f*t) * 2Pi*f

= 3/2*13*2*Pi*2028 Cos( 2Pift)

therefore peak value is Ip= 3*13*Pi*2028 = 248474.8461 A

Irms= Ip* sqrt(2) = 351396.4972

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