I found the velocity for the first part to be -0.441401, but I can\'t get the he

Question

I found the velocity for the first part to be -0.441401, but I can't get the height.

A small block of mass 55 g is released from rest, at the top of a curved frictionless wedge of mass 314 g which sits on a frictionless horizontal surface as shown. The acceleration due to gravity is 9.81 m/s2. Right is the positive direction. When the block leaves the wedge, its velocity is 2.52 m/s to the right. What is the velocity Vb of the wedge after the block reaches the horizontal surface? Answer in units of m/s What is the height h of the wedge? Answer in units of m

Explanation / Answer

K=1/2mv^2

so K= 1/2(.055kg)(2.52)^2

energy conservation

so Ksmall= 0.1746

K(big)=.030589

Potiential= K(big)+K(small)=0.2051889= mgh you can plug in and find

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