What magnitude of force must the worker apply? How much work is done on the crat

Question

What magnitude of force must the worker apply?

How much work is done on the crate by the worker's push?

How much work is done on the crate by friction?

How much work is done by gravity?

What is the net work done on the crate?

A factory worker moves a 27.0kg m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and the floor is 0.300. What magnitude of force must the worker apply? How much work is done on the crate by the worker's push? How much work is done on the crate by friction? How much work is done by gravity? What is the net work done on the crate? kg crate a distance of 5.00m

Explanation / Answer

since crate is moving with constant velocity

forces on it should be zero

Force applied by man = frictional force

frictional force = u M g

frictional force = 0.3*27*9.81

frictional force = 79.461 N

1) force applied by man on crate = 79.461 N

2) work done = F * displacement

work done by man = 79.461 *5

work done by man = 397.305 J

3) work done by friction = F * displacement

since friction is opposite to displacement

work done = - 79.461*5

work done by friction =- 397.305 J

4) since no displacement in vertical direction

work done by gravity = 0J

5) total work done = work by man + work by friction+ work by gravity

total work = 397.305-397.305+0

total work = 0J

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