in the figure below are three vectors. vector a has a length of 33, B\'s length

Question

in the figure below are three vectors. vector a has a length of 33, B's length is 67, and C is 24.Find the following

At what angle above and below the horizontal line could Vector A be at so A x B= 0?

(a) 90 degrees above, or 70 degrees below

(b) 20 degrees above, or 160 degrees below

(c) 90 degrees above, or 90 degrees below

(d) 110 degrees above, or 70 degrees below

in the figure below are three vectors. vector a has a length of 33, B's length is 67, and C is 24.Find the following B (A+B)= At what angle above and below the horizontal line could Vector A be at so A x B= 0? (a) 90 degrees above, or 70 degrees below (b) 20 degrees above, or 160 degrees below (c) 90 degrees above, or 90 degrees below (d) 110 degrees above, or 70 degrees below

Explanation / Answer

A= (33 cos 70) i+ (33 sin 70) j

B= (67 cos 20) i + (67 sin 20) j

C= (24 cos 70) i - (24 sin 70) j

i and j are unit vector along horizontal and vertical direction. :)

go for B(A+C)this time!! :) put all above values and calculte.(use google calculator to find cos 70/ sin 20)

for last case the "b" option is correct. this is when we have 0/180 deegre angle between A and B vector to vanish their cross product. good luck!

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