When at the highest position, the skater shown in the picture is at h1= 10.5 m a

Question

When at the highest position, the skater shown in the picture is at h1= 10.5 m above ground. In the second position, he is at h2 = 6.5 m. If he starts at rest at h1, if his mass is m= 99 kg and if g =10 N/kg, what is his kinetic energy in Joules when at h2?

When at the highest position, the skater shown in the picture is at h1= 10.5 m above ground. In the second position, he is at h2 = 6.5 m. If he starts at rest at h1, if his mass is m= 99 kg and if g =10 N/kg, what is his kinetic energy in Joules when at h2?

Explanation / Answer

final Ke = change in PE

= m*g*(h1-h2)

= 99*10*(10.5-6.5)

= 3960 J

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