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The 2.0 kg object below is released from rest at a height of 5.0 m on a curved f

ID: 1287384 • Letter: T

Question

The 2.0 kg object below is released from rest at a height of 5.0 m on a curved frictionless ramp. At the foot of the ramp is a spring of force constant k = 450 N/m. The object slides down the ramp and into the spring, compressing it a distance x before coming momentarily to rest.

(a) Find x. (in m)

(b) What happens to the object after it comes to rest?

The 2.0 kg object below is released from rest at a height of 5.0 m on a curved frictionless ramp. At the foot of the ramp is a spring of force constant k = 450 N/m. The object slides down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. (a) Find x. (in m) (b) What happens to the object after it comes to rest?

Explanation / Answer

a)

mgh = (1/2) mv^2

speed of block at the botteom of ramp is

v = (2 * 9.8 * 5 m ) ^ (1/2)

= 9.899 m/s

According to conservation of energy

(1/2) mv^2 = (1/ k x^2 )

x = (m/k)^ (1/2) v

= ( 2 / 450 )^ (1/2) (9.899 m/s)

= 0.659 m

after come to rest it bounce back.