A 18 g ball of clay traveling east at 3.2 m/s collides with a 30 g ball of clay

Question

A 18 g ball of clay traveling east at 3.2 m/s collides with a 30 g ball of clay traveling north at 2.0 m/s. What are the speed and the direction of the resulting 48 g ball of clay? m/s north of east Three identical train cars, coupled together, are rolling east at 2.2 m/s . A fourth car traveling east at 4.4 m/s catches up with the three and couples to make a four-car train. A moment later, the train car's hit a ?fth car that was at rest on the tracks, and it couples to make a five-car train. What is the speed of the ?ve-car train? m/s

Explanation / Answer

1) applying COM in both directions we get:-

18*3.2 = 48*v        where v is resulting velocity of the clay

=>v = 1.2m/s eastward

now again applying it in north we get as:-

30*2=48*v

=>1.25m/s northwards

hence the resultant = 1.732m/s

and the direction will be 46.17degrees

2) let the mass of each car be m

and let the speed of the car after joining be v

hence applying COM we get:-

3m*2.2+m*4.4 m*0 = 5m*v

=>v=2.2m/s

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