A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was
ID: 2258486 • Letter: A
Question
A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N A 18 g bullet pierces a sand bag 25 cm thick. If the initial bullet velocity was 57 m/s and it emerged from the sandbag with 29 m/s, what is the magnitude of the friction force (assuming it to be constant) the bullet experienced while it traveled through the bag? 87 N 0.87 N 8.7 N 22 N 87 N 0.87 N 8.7 N 22 NExplanation / Answer
a =Vf^2-Vi^2/2d =29^2-57^2/(2*0.25)
a=4816 m/s^2
f=ma =18*10^-3*4816
f=87 N
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.