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2. A long piece of wire with a mass of 0.190 kg and total length of 4.00 m is us

ID: 1288758 • Letter: 2

Question

2.

A long piece of wire with a mass of 0.190 kg and total length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hinged along a horizontal side, carries a 3.80 A current, and is placed in a vertical magnetic field with a magnitude of 0.0100 T.

(a) Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium.
   with the vertical

(b) Find the torque acting on the coil due to the magnetic force at equilibrium.
  N m

1. Consider the mass spectrometer shown schematically in the figure below. The electric field between the plates of the velocity selector is 6900 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0960 T. Calculate the radius r of the path for a singly charged ion with mass m = 4.17 2. A long piece of wire with a mass of 0.190 kg and total length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hinged along a horizontal side, carries a 3.80 A current, and is placed in a vertical magnetic field with a magnitude of 0.0100 T. (a) Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. with the vertical (b) Find the torque acting on the coil due to the magnetic force at equilibrium. N m x 10^-26kg. r = m

Explanation / Answer

1.

speed of velocity selector

v=E/B =6900/0.096=71875 m/s

centripetal force =magnetic force

mv2/r=qvB

=>r=mv/qB =(4.17*10-26)(71875)/(1.6*10-19)*0.096

r=0.195 m

2.

Number of turns

N=L/4a=4/(4*0.1)=10 turns

At equilibrium

Tg=TB

mg(L/2)SIn(o) =NIL2BCos(o)

tan(o)=2NILB/mg

o=tan-1(2NILB/mg)=tan-1(2*10*3.8*0.1*0.01/0.19*9.8)

o=2.34o

b)

Torque due to magnetic force

T=NIL2BCos(o)=10*3.8*0.12*0.01*Cos(2.34)

T=3.8*10-3 N-m