2. A football is kicked ( at ground level) at an angle of 37degrees with a veloc
ID: 1725467 • Letter: 2
Question
2. A football is kicked ( at ground level) at an angle of 37degrees with a velocity of 20 m/s
Calculate:
The max. height
the time of travel until it hits the ground.
how far away does it travel
the velocity vector at max height
the acceleration at max height
If the player wants to make a field goal, and the goal posts are30m away, will the ball pass over the 5m horizontal post?
b) Suposse the player " punts the ball, not from the groundbut at 1m high ( holding the ball with his hands)
How far did the ball travel before hitting the ground?
Explanation / Answer
Given 1) initial velocity of thefoot ball u = 20 m/s angle ofprojectile = 37 degrees a) maximum height H = u2sin2 / 2 g = (20) 2 sin2 37 / 2*9.8 = 7.3914 m b) time t = 2 u sin /g = 2 x 20 x sin 37 / 9.8 = 2.4563 s c) Horizontal range R =u2 sin 2 / g = (20)2 ( sin 2x 37 ) / 9.8 = 39.2351 m d) Velocity at maximumheight v2 - u2 = 2gH v2 = (20)2 + 2 x 9.8 x 7.3914 v= 23.3424 m/s e) Acceleration at maximum height h = ut + (1/2 ) at2 7.3914=( 23.3424 ) (1.2281) + 0.5 x ax(1.2281)2 a = -28.2122 m/s2 here negative sign represents opposite direction 2) range = ut = u 2 h / g = (23.2434 )2 x 1 / 9.8 = 10.5 mRelated Questions
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