C Homework Help Ask A Que x ncourse: 2014 Fall PHYs 21 x dle2 du/plug x C fi moo

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C Homework Help Ask A Que x ncourse: 2014 Fall PHYs 21 x dle2 du/plug x C fi moodle2.lsu.edu file.php/1036704/mod resource/content/1/WHW 8 moodle.pdf E: Apps 15u Lsu B Tiger Mai 15u Paws e sTUDYBLUE Khan Academy L CAE Test Scheduler L Wiley Plus 1. (10 PTS n the ammonia (NH3) molecule of the figure, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d 9.40 x 10 "m rom each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen distance is L 0.14 x 10 m. What are the (a) x and (b) y coordinates of the molecule's center of mass? 2. (10 PTS n the figure puck 1 of mass m 0.50 kg is sent sliding across a frictionless lab bench, to undergo a one-dimensional elastic collision with stationary puck 2. Puck 2 then slides off the bench and lands a distance d from the base of the bench. Puck 1 rebounds from the collision and slides off the opposite edge of the bench, landing a distance 5d from the base of the bench. What is the mass of puck 2 (Hint: Be careful with signs.) Other Bookmarks

Explanation / Answer

1)

We can easily obtain the side length and length of the altitude of equilateral triangle from its properties. And the values are d*sqrt(3) and 3d/2.

xcom = [mH(d)+mH(-d/2)+mH(d/2)+mN(0)] / (3mH+mN) . By subtituing the given values we get

xcom = 0.55621*10^-11.

similarly ycom = [mH(0)+mH(0)+mH(0)+mN(sqrt(L^2-d^2))] / (3mH+mN) = 0.225 *10^-11

So, COM is (0.55621*10^-11, 0.225 *10^-11).

2)

Key Observations: 1) the time taken by the bodies to reach the ground is same for both since both have a downward accleration of g and intial along that direction zero.

2) Since horizontal distance travelled on the ground will depend on the velocity in that direction, the ratio of final velocity magnitudes is 5:1.

From the above observations and the formula v1-v2 = u2-u1 for elastic collision we can obtain the mass ratio.

Let v1 = -5*v then v2 =v and we know u2=0. Therefore, u1 = 6v.

we also know that m1(v1-u1) = m2(u2-v2) . Hence, m2=11*m1 = 5.5kg

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