A 2 kg mass is attached by a string that is 1 m long, and swung around in a circ

Question

A 2 kg mass is attached by a string that is 1 m long, and swung around in a circular path at a constant speed. The tension on the string is 10 newtons. Calculate the following:
A. Centripetal acceleration in m/s^2 B. Angular velocity of the mass in rad/s C. Tangential velocity in m/s A 2 kg mass is attached by a string that is 1 m long, and swung around in a circular path at a constant speed. The tension on the string is 10 newtons. Calculate the following:
A. Centripetal acceleration in m/s^2 B. Angular velocity of the mass in rad/s C. Tangential velocity in m/s
A. Centripetal acceleration in m/s^2 B. Angular velocity of the mass in rad/s C. Tangential velocity in m/s
A. Centripetal acceleration in m/s^2 B. Angular velocity of the mass in rad/s C. Tangential velocity in m/s

Explanation / Answer

Centripetal acceleration=Tension of string=10N

.

A. Centrietel Force=m*centripetal acceleration

            10=2*a

            a=5 m/s2

.

B. Acceleration=w2/R

            5=w2*R

            w=2.236 rad/s2.

.

C. Tangential velocity=w*R

                        =2.236*1=2.36 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.