Two identical masses are attached to two identical springs that hang vertically.
ID: 1289565 • Letter: T
Question
Two identical masses are attached to two identical springs that hang vertically. The two masses are pulled down and released, but mass B is pulled further down than mass A.
a) Which mass will take a longer time to reach the equilibrium position? Explain.
b) Which mass will have the greater acceleration at the instant of release, or will they have the same acceleration? Explain.
c) Which mass will be going faster as it passes through equilibrium, or will they have the same speed? Explain.
d) Which mass will have the greater acceleration at the equilibrium point, or will they have the same acceleration? Explain.
Explanation / Answer
a) both will reach at the same time
b) a = -w^2 * y
yb > ya
mass B
c) V = W*y
yb > ya
massB
d) same accelaration a = 0
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