Two identical masses are attached by a light string thatpasses over a small pull

Question

Two identical masses are attached by a light string thatpasses over a small pulley. One of the masses rests on a flat tabletop while the other hangs over the edge (assume this mass does nottouch the ground). The table and the pulley are frictionless. Themasses are moving: 1. At constant speed. 2. With an acceleration greater than g. 3. With an acceleration less than g. 4. With an acceleration equal to g. Two identical masses are attached by a light string thatpasses over a small pulley. One of the masses rests on a flat tabletop while the other hangs over the edge (assume this mass does nottouch the ground). The table and the pulley are frictionless. Themasses are moving: 1. At constant speed. 2. With an acceleration greater than g. 3. With an acceleration less than g. 4. With an acceleration equal to g.

Explanation / Answer

let the mass of the block is m. for the block hanging in the air let T be the tension in thestring.As the pulley is frictionless so tension will be same onboth sides of pulley. So the same tension T acts on the block lying on the table. Now let the hanging block is moving with an acceleration adownwards. so the equation of motion for this block will be mg-T = ma ----------------------1 for the block on table T is the only force.(if we assume thatstring is inextensible then the acceleration of both the blockswill be same) hence equation of motion for this block T = ma-----------------------2 by adding equation 1 &2 we get 2ma = mg a = g/2 Hence the acceleration will be less than g.

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