A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of some

Question

A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of some other liquid floats atop the gasoline. This floating liquid has an index of refraction greater than 1.00 but less than 1.40. The floating layer is 242 nm thick. Light traveling through the air with a wavelength of 625 nm is incident perpendicularly onto this film, and as a result the film looks very bright in this color to an observer looking down onto the film from above. Assuming that the film is the minimum thickness for which this could occur, what is the index of refraction of this floating liquid?

Explanation / Answer

The formula to apply is 2nt = m(wavelength(

2(n)(242 X 10-9) = 1(625 X 10-9)

n = 1.29

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