(a) A horizontal long strait wire carries a current of I1 = 8 A from left to rig

Question

(a) A horizontal long strait wire carries a current of I1 = 8 A from left to right. The wire is tangential to a circular loop of wire of radius R = 0.03 m lying immediately below it. The loop carries a current of I2 = 2 A in the counter-lockwise direction. Assuming that the thicknesses of the wires are negligible, find the magnitude and direction of the net magnetic field at the center of the circular loop. Explain your reasons for the direction briefly but clearly.

(b) A second long wire, also carrying a current L1 = 8A from left to right, is added and lies parallel to the first wire, tangential to the loop but immediately below the loop. Find the magnitude and direction of the net magnetic field at the center of the circular loop.

(c) Find the magnitude and direction of the net magnetic field at the center of the circular loop if the direction of the current I1 = 8A in the second wire lying below the loop is reversed so that it flows from right to left.

(d) Find the magnitude and direction of the net magnetic field at a point midway between the two horizontal wires if the circular loop is removed and each of the wires carries a current I1 = 8A from left to right. The two wires are, as before, 0.03 m from each other.

Explanation / Answer

using right hand thumb rule,

direction of magnetic field due to wire due to is downward at center of circle,whereas due to loop, it is upward

so net magnetic field

B=Bw-Bl

Bw=u0*i1/2*pi*r

Bl=u0*i2/2*r

we know i1, i2 and r

so we can know net B

direction of net magnetic field, if the magnitude due to wire is more it will be downwards, otherwise it is upwards.

we can find other parts also , using same method.

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