Thin lens Equation 1. Calculate the image position and height of a 2.0-cm-tall o

Question

Thin lens Equation

1. Calculate the image position and height of a 2.0-cm-tall object is 40 cm in front of a converging lens that has a 20 cm focal length.

2. Calculate the image position and height of a 1.0-cm-tall object is 10 cm in front of a converging lens
that has a 30 cm focal length

3. Calculate the image position and height of a 2.0-cm-tall object is 15 cm in front of a diverging lens
that has a -20 cm focal length.

4. Calculate the image position and height of a 1.0-cm-tall object is 60 cm in front of a diverging lens
that has a -30 cm focal length.

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Explanation / Answer

1) 1/p + 1/q = 1/f

1/40 + 1/q = 1/20

1/q = 1/20 - 1/40 = 1/40

q = 40 cm

M = -q/p = -40/40 = -1

so h' = -2 cm

2) 1/10 + 1/q = 1/30

1/q = 1/30 - 1/10 = 1/30 - 3/30 = -2/30 = -1/15

q = -15 cm

M = -q/p = 15/10 = 1.5

h' = 1.5*1 = 1.5 cm

3)

1/15 + 1/q = -1/20

1/q = -1/20 - 1/15 = -3/60 - 4/60 = -7/60

q = -60/7=-8.57 cm

M = 8.57/15 = 0.571

h' = 1.14 cm

4) 1/60 + 1/q = -1/30

1/q = -2/60 - 1/60 = -3/60 = -1/20

q = -20 cm

M = 20/60 = 1/3

h' = 1/3*1 = 0.33

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