Two people carry a heavy electric motor by placing it on a light board 1.50m lon

Question

Two people carry a heavy electric motor by placing it on a light board 1.50m long. One person lifts at one end with a force of 420N , and the other lifts the opposite end with a force of 690N .

PART A: What is th weight of the motor? W IS 1110N

PART B: Where along the board is its center of gravity located? .932 m from end where 420-N force is applied

PART C: Suppose the board is not light but weighs 220N , with its center of gravity at its center, and the two people each exert the same forces as before. What is the weight of the motor in this case?w = 890N

I have the first 3 questions correct but:

Part D

Where is its center of gravity located?

_______________________ m from the end where the 420-Nforce is applied

** It is not .93...**

Explanation / Answer

Let it is at a distance x from 420 N end.

Balancing torque, we get

420*x= 690*(1.5-x)

1110x= 690*1.5

x= 0.93m

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