The dissociation energy of a molecule is the energy required to break apart the

Question

The dissociation energy of a molecule is the energy required to break apart the molecule into seperate atoms. The dissociation energy for a particular molecule is 1.25x10^-18J. Suppose that this energy is provided by a single photon. Determine the wavelength (a) and frequency of the photon (b). In what region of the electromagnetic spectrum does the photon lie? (C)
part a= 15.9x 10^-8 m Part b? Part c?
The dissociation energy of a molecule is the energy required to break apart the molecule into seperate atoms. The dissociation energy for a particular molecule is 1.25x10^-18J. Suppose that this energy is provided by a single photon. Determine the wavelength (a) and frequency of the photon (b). In what region of the electromagnetic spectrum does the photon lie? (C)
part a= 15.9x 10^-8 m Part b? Part c?

part a= 15.9x 10^-8 m Part b? Part c?

Explanation / Answer

E = h f

the energy of a photon is equal to the planck's constant times the frequency of the photon.

(energy) = (planck's constant) (frequency)

rearranging this

E/h = f
f = (1.24 E-18 J)/(6.626E-34 J s)
f = 1.87 E15 s-1
f = 1.87 E15 Hz

ok so using this frequency we can calculate the wavelength (lambda)
here the velocity of light is c

v = lambda*f
c/f = lambda
lambda= 2.998E8/1.87E15
lambda = 1.60E-7 m

this lies on the infrared to red region on the electromagnetic spectrum...

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