A railroad train is traveling at 25.0m/s in still air. The frequency of the note

Question

A railroad train is traveling at 25.0m/s in still air. The frequency of the note emitted by the locomotive whistle is 408Hz

Part A
What is the wavelength of the sound waves in front of the locomotive?

_____________m

Part B
What is the wavelength of the sound waves behind the locomotive?

__________________m

Part C

What is the frequency of the sound heard by a stationary listener in front of the locomotive?
___________________Hz

Part D
What is the frequency of the sound heard by a stationary listener behind the locomotive?
___________________Hz

Please show work!! Thank you!!

Explanation / Answer

let speed of sound in air = 343 m/s

(A) Wavelength would be 343 m/s / 408 hz = 0.841 m
(B) (343 + 25.0)/343*0.841 =0.902 m behind the train.
(C) The forward observer would experience the frequency as 408 x (343+25.0)/343 hz = 437.74 hz

(D) Rearward observer would experience the frequency as 408 x (343-25.0)/343 hz. = 378.26 hz

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