A 0.18-kg stone is held 1.2m above the top edge of a water well and then dropped

Question

A 0.18-kg stone is held 1.2m above the top edge of a water well and then dropped into it. The well has a depth of 5.6m. (a) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone?Earth system before the stone is released. 2.3 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four -digit accuracy to minimize roundoff error. J (b) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone?Earth when it reaches the bottom of the well? The response you submitted has the wrong sign. J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well? J

Explanation / Answer

#a)

U1 = PE = m*g*h1 = 0.18*9.8*1.2 = +2.1168 J

#b)

U2 = PE = m*g*-h2 = -(0.18*9.8*5.6) = -9.8784 J

c)

dU = U2 - U1

dU = -11.9952 J

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