A cross between GgWw x GgWw. G=Yellow, g = green, W= round, w= wrinkled. There i

Question

A cross between GgWw x GgWw. G=Yellow, g = green, W= round, w= wrinkled.
There is a 9:3:3:1 ratio of pea plants(yellowround:yellowwrinkled:greenround:greenwrinkled). Therefore the probability of obtaining a wrinkled green seed is 1/16th.

Now, what is the probability of obtaining precisely 2 wrinkled green seeds from a set of seven GgWw seeds?

There is a hint given: probability of ggww is p; by definition q= 1-p

I do not understand the relevance of the hint. I think I am overthinking this problem.

Explanation / Answer

The probability of obtaining a wrinkled green seed from a dihybrid heterozygous cross is 1/16. This is equal to 0.06. This is q. As p +q = 1, p = q - 1 p = 0.06 - 1 p = 0.94 --------------------------------- Keeping the same values of p and q, we consider the next case. A set of seven heterozygous seeds gives us 3 crosses. Each cross gives 16, hence 3 crosses give 48. As each cross gives one wrinkled green, three crosses give 3 wrinkled green seeds. A ratio of 3/48 gives us 0.18. --------------------------------- You can also put it in this way: Each cross has a q value of 0.06, hence three crosses give 0.18. ---------------------------------- Hence the probability of obtaining one green wrinkled seed is 3/48. So, the probability of obtaining two wrinkled seeds would be 3/48 + 3/48 = 6/48= 0.12

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.