A certain loudspeaker has a diameter of 31 cm. At what frequency will the wavele

Question

1. A certain loudspeaker has a diameter of 31 cm. At what frequency will the wavelength of the sound it emits in air be equal to its diameter? (Note: If the wavelength is large compared to the diameter of the speaker, then the sound waves spread out almost uniformly in all directions from the speaker; but when the wavelength is small compared to the diameter of the speaker, the wave energy is propagated mostly in the forward direction.) The speed of sound is 343 m/s. The SI unit of frequency is "Hz".
2. If two successive harmonics of a vibrating string are 275Hz and 330Hz, what is the frequency of the fundamental?

Explanation / Answer

We know that lambda=0.31m and v=343m/s.

v = lambda * f

f = 343/0.31 = 1106 Hz

2)

the fundamental, which is the 1st harmonic, is the (n+1)th harmonic minus the nth harmonic
330-275 = 55Hz

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