Clear answers please. A solid sphere of mass m floats in a beaker of water as sh

Question

Clear answers please.

A solid sphere of mass m floats in a beaker of water as shown. A second sphere of the same material but of mass 2m placed in a second beaker of water. In the space provided, sketch the final position of the second sphere. In its final position, how docs the buoyant force on the larger sphere compare to its weight? How does the volume displaced by the larger sphere compare to that display by the smaller sphere? Are your answer to questions a and b consistent with Archimedas' principlke? Explain.

Explanation / Answer

The second sphere will be submerged in the same proportion as first sphere'

when the mass is doubled the volume of the sphere slso doubles because density(mass/vo;ume) is constant

the volume of water replaced by second sphere also doubles. the percentage of material submerged depends on the ratio of density of material and water.

a)

The buyont force on the larger sphere will be exactly equal to its weight

B = 2mg

b)

volume of water displaced by larger sphere is double the volume diaplaced by the smaller sphere because mass of larger sphere is double the smaller sphere.

the mass of water displaced is equal to mass of material. As density is constant, to double the mass of water displaced, volume of water displaced should be doubled

c) a and b are consistent with Archimedes' principle as explained bove

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

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