A 200-loop coil of cross sectional area 8.5 cm 2 lies in the plane of the page.

Question

A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds.

The magnitude of the average voltage induced in the coil as the external flux is changing is 0.570 V

(a) What is the magnitude of the change in the external magnetic flux enclosed by the coil?

_____________ T?m^2

Explanation / Answer

induced emf is defiend as the rate of change of magnetic flux
in mathematical form,
induced emf e = NAdB/dt
where A = area
N = no. of tunrs
dB/dt = rate of change of amgnetic flux

also induced current i = emf/R

so emf e = iR = 0.14 *4 = 0.56 volts

a. chnage of magnetic flux = A dB

= 200 * 8.5*10^-4 * (0.06-0.02)

= 6.8 *10^-3 Tm^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.