An object is placed 10 m before a convex lens with focal length 5.8 m . Another

Question

An object is placed 10 m before a convex lens with focal length 5.8 m . Another convex lens is placed 9.95 m behind the ?rst lens with a focal length 3.3 m (see the ?gure below). Note: Make a ray diagram sketch in order to check your numerical answer

(1) At what distance is the ?rst image from the
?rst lens?
Answer in units of m

(2) What is the magni?cation of the ?rst image?

(3) At what distance is the second image from thesecond lens? Answer in units of m

(4) What is the magni?cation of the ?nal image,when compared to the initial object?

Explanation / Answer

Part 1)

Apply 1/f = 1/p + 1/q

1/5.8 = 1/10 + 1/q

q = 13.8 m

Part 2)

M = -q/p

M = -13.8/10

M = -1.38 (Negative means inverted)

Part 3)

Since the lenses are 9.95 m apart, the first image is 13.8 - 9.95 = 3.86 m behind the second lens.

So 1/f = 1/p + 1/q

1/3.3 = 1/-3.86 + 1/q

q = 1.78 m

M = -q/p for this lens

M = -1.78/-3.86

M = .461

Thus the total M = .461(-1.38)

M = -.636 (Again, the negative means inverted)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.