(a) What is the tangential acceleration of a bug on the rim of a 13.0-in.-diamet

Question

(a) What is the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 75.0 rev/min in4.50 s?
m/s2

(b) When the disk is at its final speed, what is the tangential velocity of the bug?
m/s

(c) One second after the bug starts from rest, what is its tangential acceleration?
m/s2

(d) One second after the bug starts from rest, what is its centripetal acceleration?
m/s2

(e) One second after the bug starts from rest, what is its total acceleration?

Explanation / Answer

A. Angular speed,w = 2*pi*N/60 = 7.8rad/s

Tangential accelration, A = r*dw/dt = 0.299 m/s2

B. Tangential velocity ,V = r*w= 1.489 m/s

C. Tangential acc. after 1s = 0.057 m/s2

D. Centripetal acc. After 1s = r*w^2 = 0.017 m/s2

E. Total acc. = At +Ac = 0.074 m/s2

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.