The following reaction is one of the step in the glycolytic pathway Glucose -6-p

Question

The following reaction is one of the step in the glycolytic pathway
Glucose -6-phosphate <----> fructose-6-phosphate
The equilibrium constant is Keq for this reaction at 25degree celsius is 0.5.
a) assume that you incubate a solution containing 0.15M glucose-6-phosphate (G6P) overnight at 25 degree celsius with the enzyme phosphoglucoisomerase that catalyzes reaction above. How many millimoles of fructose-6-phosphate (F6P)will you recover from 10 ml of the incubation mixture the next morning, assuming you have an appropriate chromatographic procedure to separate F6P from G6P?

Explanation / Answer

G6P F6P
I 0.15 0
C -x +x
E 0.15-x x
Keq=[F6P]/[G6P]=x/(0.15-x)=0.5. From this, x=0.05M
(0.05M)(10mL)=0.5mmol

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