A 0.267m -long bar moves on parallel rails that are connected through a 6.34 Ohm
ID: 1306489 • Letter: A
Question
A 0.267m -long bar moves on parallel rails that are connected through a 6.34 Ohm resistor, as shown in the following figure (Figure 1), so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform magnetic field 1.27T that is directed into the plane of the figure. At an instant when the induced current in the circuit is counterclockwise and equal to 1.70A , what is the magnitude of the velocity of the bar? Express your answer with the appropriate units. What is the direction of the velocity of the bar?Explanation / Answer
1, we knoe E = v cross B *L
E = V * 1.27 * 0.267 = V* 0.338
now CURRENT = E/R = V*0.338/6.24 = 1.70
V = 31.78 M/S
2. NOW WE KNOW DIRECTION OF CURRENT DEPENDS ON V CROSS B SO BY IT WE GET RIGHTWARD AS VELOCITY OF BAR
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