A 0.25-kg block resting on a frictionless, horizontal surface is attached to a s
ID: 1988198 • Letter: A
Question
A 0.25-kg block resting on a frictionless, horizontal surface is attached to a spring having force constant 83.8 N/m as in Figure P13.16. A horizontal force F causes the spring to stretch a distance of 5.46 cm from its equilibrium position. Find the value of F.
A 0.25-kg block resting on a frictionless, horizontal surface is attached to a spring having force constant 83.8 N/m as in Figure P13.16. A horizontal force vector F causes the spring to stretch a distance of 5.46 cm from its equilibrium position. Find the value of F. What is the total energy stored in the system when the spring is stretched? Find the magnitude of the acceleration of the block immediately after the applied force is removed. Find the speed of the block when it first Reaches the equilibrium position. If the surface is not frictionless but the block still reaches the equilibrium position, how would your answer to part (d) change? What other information would you need to know to find the actual answer to part (d) in this case?Explanation / Answer
F = kx = 83.8 * 0.0546 = 4.58 N
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