A 0.200-m uniform bar has a mass of0.760 kg and is released from rest inthe vert
ID: 1727645 • Letter: A
Question
A 0.200-m uniform bar has a mass of0.760 kg and is released from rest inthe vertical position, as the drawing indicates. The spring isinitially unstrained and has a spring constant of k =28.5 N/m. Find the tangential speedwith which end A strikes the horizontal surface. A 0.200-m uniform bar has a mass of0.760 kg and is released from rest inthe vertical position, as the drawing indicates. The spring isinitially unstrained and has a spring constant of k =28.5 N/m. Find the tangential speedwith which end A strikes the horizontal surface. A 0.200-m uniform bar has a mass of0.760 kg and is released from rest inthe vertical position, as the drawing indicates. The spring isinitially unstrained and has a spring constant of k =28.5 N/m. Find the tangential speedwith which end A strikes the horizontal surface.Explanation / Answer
to solve this we use the law of conservation ofenergy
the moment of inertia of the bar is given by
I = (1 / 3) m L2 L is thebar length and
= v / L
to find the speed of point A so that
Eup = m g h
=Edown
= (1 / 2) I2 + (1 / 2) k x2
from the drawing we can see that
x = [(0.100 m)2 + (0.200m)2] - (0.100 m)
= ......... m
h = (L / 2)
solving for v we get
v = [3(m g L - k x2) / m]
= ........ m / s
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