A 0.200-H inductor is connected to a 60.0-Hz 120-V rms source. (a) What is the i

Question

A 0.200-H inductor is connected to a 60.0-Hz 120-V rms source.

(a) What is the inductive reactance?

(b) What is the rms current to the inductor?

(c) If both the inductance and the frequency were doubled, what would be the rms current?

For a), I am pretty sure it is simply XL = 2PifL = (2Pi)(60)(0.200) = 75.39822369 Ohms

If so, I get Z = 825.9461582 and then Irms = 0.1452879208 A

If all this is correct, then I guess I redo equations doubling frequenzy and L for inductance. Is that right?

A 0.200-H inductor is connected to a 60.0-Hz 120-V rms source. (a) What is the inductive reactance? (b) What is the rms current to the inductor? (c) If both the inductance and the frequency were doubled, what would be the rms current? For a), I am pretty sure it is simply XL = 2PifL = (2Pi)(60)(0.200) = 75.39822369 Ohms For b), It looks like I need to use Vrms = IrmsZ and rearranged to Irms = Vrms/Z. But I am confused on how to calculate for Z = The is no capacitor so should I be using 0 as the value for XC? If so, I get Z = 825.9461582 and then Irms = 0.1452879208 A If all this is correct, then I guess I redo equations doubling frequency and L for inductance. Is that right?

Explanation / Answer

GREAT JOB ON PART A!

***********

For part B, as there is nor R and C,

Z = XL

Thus,

I = Vrms / XL = 1.59 A   [ANSWER]

*************

If we double inductance and frequency,

XL = w L

will be multiplied by 4. Hence, current will be divided by 4,

I = 0.398 A   [ANSWER]

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.