1.) A convex mirror with a radius of curvature of 38.0 cm forms a 0.99 cm tall i

Question

1.) A convex mirror with a radius of curvature of 38.0 cm forms a 0.99 cm tall image of a pencil at a distance of 11.7 cm behind the mirror. Calculate the object distance for the pencil and its height. Is the image real or virtual? What is the magnification? Is the image inverted or upright?

object's location

_____cm

object's height

______cm

________magnification

2.) A convex mirror is placed on the ceiling at the intersection of two hallways. If a person stands directly underneath the mirror, the person's shoe is a distance of 190.6 cm from the mirror. The mirror forms an image of the shoe that appears 11.9 cm behind the mirror's surface. What is the mirror's focal length? What is the magnification of the image? Is the image real or virtual? Is the image upright or inverted?

Focal Length _____cm

Magnification ______cm

Nature

a.) real

b.) virtual

c.) upright

d.) inverted

object's location

_____cm

object's height

______cm

________magnification

Explanation / Answer

1) 1/u+!/v=1/f

or 1/u -1/11.7 =-2/38

or u=30.45 cm

h'/h=v/u

or 0.99/h=11.7/30.45

or h=2.576 cm

magnification=v/u

=0.99/2.576

=0.384

2)1/u+1/v=1/f

or 1/190.6 -1/11.9=1/f

or f=-12.69 cm

focal length=-12.69 cm

magnification=v/u

=11.9/190.6

=0.062

the image is virtual and upright

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