(((QUESTION 1))) A uniform meterstick pivoted at its center has a 100g mass susp

Question

(((QUESTION 1)))

A uniform meterstick pivoted at its center has a 100g mass suspended at the 21.0cm position.

Part A

At what position should a 85.0g mass be suspended to put the system in equilibrium?

Part B

What mass would have to be suspended at the 90.0cm position for the system to be in equilibrium?

(((QUESTION 2)))

A fixed 0.16-kg solid-disk pulley with a radius of 0.080m is acted on by a net torque of 7.2m?N .

Part A

What is the angular acceleration of the pulley?

Express your answer using two significant figures.

Explanation / Answer

a) 100*29=85*x

x=34.12

so at 50+34.12=84.12 cm

b) 100*29 = m*40

m=72.5 g

c) I of pulley =m*r*r = .16*.08*.08 = 0.001024 kgm^2

T = I* alpha

alpha = 7.2/0.001024 = 7031.25 rad/s^2

If T = 7.2 milliNm

alpha will be 7.03125 rad/s^2

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